Can you figure this out?

[Velvet]

"Three Friends, A, B & C went to a restaurant. After dinner they asked for the bill, the amount came to $30 /- They decided to pay the bill amount on equal share.
Everybody took out $10 /- each and paid the bill.

The waiter realized that the amount of their bill was $25 /- and not $30 /- He took $ 5 /- from counter and decided to return it to them. Then he thought there are 3 how will they share $5 /- ?
So he decided to keep $2 /- for himself and return only $3 /- to them.

He came to their table and returned them $3 /- with apologies.
Everybody took $1 /-.

Now the question is everyone paid $10 /-
but later they get $1 /- refunded. So everybody paid $9 /-

$9 x 3 = $27 /-

The waiter keeps $2 /- for himself.

$27 + $2 = 29

So...... Where is the remaining $1 /- ???"



I'm sure this has been done before, but can someone explain where the other $1 is?

[westdoor]

I think the remaining dollar is "lost" in the rounding up / down of the spliting of the bill.

Tha actual bill was $25 which divided by 3 is $8.33 so when the friends get their $1 back the total they pay is $9.33 x 3 = $28 which leaves $2 for the waiter.

[seb]

The calculation should be $27 - $2 (not $27 + $2), because the waiter keeps $2. Then nothing is missing

[seb]

Because the bill is $25 (=$27 - $2)

[carang]

bill = $25
waiter= $ 2
customers=$3
______________
$30

seems to work for me....

[kamote]

fire the waiter...!!!